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Solution :

We have `y= f(x) = 2 ^({x})` <br> Now `{x}` is a periodic function with period 1. <br> Hence `f(x) = 2^({x})` is also periodic with period 1. <br> So we need to draw the graph for `x in [0, 1)` only. This part of the graph can be repeated to draw the graph in intervals `[n , n+1), n in Z`. <br> For `" "x in [0, 1), {x}=x` <br> `therefore" "y= 2^(x), x in [0, 1)` <br> So the graph of `y=f(x)` is as follows. <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CEN_GRA_C02_E01_025_S01.png" width="80%">Transcript

Time | Transcript |
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00:00 - 00:59 | draw the graph of Y is equal to function function vyaktigat 12.2 ko Dipawali Dipawali |

01:00 - 01:59 | open 2.10.18 open 10.1 almost every unit 2.3.2 is closed interval |

02:00 - 02:59 | thank you |